https://www.ultrafractal.com/help/index.html?/help/formulas/standard/lambda.html
in case somebody interested, I found a normalisation of the lambda formula.
init
a = (p + 1) / (2 ^ p)
loop
z = (a - z^p) / a z c
https://www.ultrafractal.com/help/index.html?/help/formulas/standard/lambda.html
in case somebody interested, I found a normalisation of the lambda formula.
init
a = (p + 1) / (2 ^ p)
loop
z = (a - z^p) / a * z * c